Projectile Motion (Guy commiting suicide)

AI Thread Summary
Bob runs off a cliff at a speed of 4.2 m/s from a height of 110 meters. The equation used to determine the time to reach the water is Y = Vo*t + 1/2*a*t^2, with Y representing height, Vo as initial velocity, and a as acceleration due to gravity. The calculation yields a time of approximately 4.74 seconds for Bob to hit the water. The discussion touches on the morbid nature of the scenario while humorously suggesting Bob might have a parachute. The focus remains on the physics of projectile motion and the calculations involved.
maxtheminawes
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Homework Statement


Bob has reached the special time in his life and runs horizontally off the edge of a cliff at 4.2 m/s. If the top of the cliff is 110m above the surface of the ocean, how long does it take Bob to reach the water?

Homework Equations


Y=Vot+1/2at^2
Y=height
t=time
Vo=initial velocity


The Attempt at a Solution


-110=0+1/2(-9.8)t^2
t= sqrt of((-110)/(1/2(-9.8)))
t=4.74secs

 
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This is morbid. I hope Bob can swim, and also he has got secretly a parachute, just for the case he changes his mind during the fall. He has enough time, that you calculated correctly.

ehild
 
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