Projectile Motion stone dropped

AI Thread Summary
To determine the height from which a stone is dropped, use the formula for distance under constant acceleration, where initial velocity is zero and acceleration is due to gravity (9.8 m/s²). Given a drop time of 4.2 seconds, the height can be calculated as approximately 84.1 meters. For the kangaroo's jump, the takeoff speed can be found using the formula for vertical motion, considering the maximum height of 2.0 meters. This involves calculating the initial velocity needed to reach that height against gravitational pull. Understanding these concepts and applying the correct formulas will yield the necessary answers.
bkoiskewl1
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1)If a stone dropped (not thrown) from a bridge takes 4.2 s to hit the water, how high is the rock-dropper? Ignore friction.

2)A kangaroo can jump straight up about 2.0 m. What is its takeoff speed?


I suck at physics so yeah...
 
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bkoiskewl1 said:
1)If a stone dropped (not thrown) from a bridge takes 4.2 s to hit the water, how high is the rock-dropper? Ignore friction.

2)A kangaroo can jump straight up about 2.0 m. What is its takeoff speed?


I suck at physics so yeah...

You don't suck at physics, you just need to get in the right frame of mind:biggrin:

Check out this thread: https://www.physicsforums.com/showthread.php?t=110015" for useful formulae.

List all the variables that you know and the variables that you need to know., then find a formula that includes everything you know and one thing you don't. Substitute into the formula and you will get the answer you seek.

For your first question, you know several things:
V0 (initial velocity) = 0
a (acceleration) = g (gravity, or 9.8 m/s2)
t (time) = 4.2s
x0 (starting position) = 0

what you are looking for is
x (finishing distance)

Find the formula, plug the numbers in, find your answer.

Your second question takes a little bit more thinking, but try it out and let me know how far you get.
 
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