Projectile Motion stone dropped

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SUMMARY

A stone dropped from a bridge takes 4.2 seconds to hit the water, indicating a height of approximately 84.1 meters, calculated using the formula x = V0 * t + 0.5 * a * t², where V0 = 0 m/s, a = 9.8 m/s², and t = 4.2 s. For the kangaroo's jump, which reaches a height of 2.0 meters, the takeoff speed can be determined using the formula v = √(2 * g * h), resulting in a takeoff speed of approximately 6.26 m/s. Both calculations ignore friction and air resistance, focusing solely on gravitational effects.

PREREQUISITES
  • Understanding of basic kinematics
  • Familiarity with gravitational acceleration (9.8 m/s²)
  • Knowledge of the equations of motion
  • Ability to manipulate algebraic formulas
NEXT STEPS
  • Study the equations of motion in physics
  • Learn about free fall and gravitational acceleration
  • Explore the concept of initial velocity in projectile motion
  • Investigate the physics of jumping and takeoff speed calculations
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of motion and gravity.

bkoiskewl1
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1)If a stone dropped (not thrown) from a bridge takes 4.2 s to hit the water, how high is the rock-dropper? Ignore friction.

2)A kangaroo can jump straight up about 2.0 m. What is its takeoff speed?


I suck at physics so yeah...
 
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bkoiskewl1 said:
1)If a stone dropped (not thrown) from a bridge takes 4.2 s to hit the water, how high is the rock-dropper? Ignore friction.

2)A kangaroo can jump straight up about 2.0 m. What is its takeoff speed?


I suck at physics so yeah...

You don't suck at physics, you just need to get in the right frame of mind:biggrin:

Check out this thread: https://www.physicsforums.com/showthread.php?t=110015" for useful formulae.

List all the variables that you know and the variables that you need to know., then find a formula that includes everything you know and one thing you don't. Substitute into the formula and you will get the answer you seek.

For your first question, you know several things:
V0 (initial velocity) = 0
a (acceleration) = g (gravity, or 9.8 m/s2)
t (time) = 4.2s
x0 (starting position) = 0

what you are looking for is
x (finishing distance)

Find the formula, plug the numbers in, find your answer.

Your second question takes a little bit more thinking, but try it out and let me know how far you get.
 
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