Projectile rock hitting a moving van problem

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The discussion revolves around a physics problem involving a rock thrown by Suzie at a moving police van. The van is traveling at 3.2 m/s and is initially 5.0 meters away when the rock is thrown at 9.0 m/s at a 37-degree angle. Calculations show that the time for the rock to hit the van is 1.25 seconds, with the van's position relative to Suzie being 9.01 meters and the rock's height at impact being 0.7 meters above the ground. The method used for the calculations appears correct, but the accuracy of the numerical results has not been verified. The discussion seeks confirmation on whether any mistakes exist in the calculations.
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I have equations for the following problem and an answer, but I am not sure if they are correct:

Suzie (a geology student) is attacking a police van during a demonstration for peace and love at the University. The van is escaping at 3.2 m/s. Suzie throws her rock when the back of the van is 5.0 meters away. The rock leaves her hand at 1.6 meters above the ground, with a speed of 9.0 m/s and an angle of 37 degrees above the horizon. The rock hits and dents the back door of the van. Find the position of the van (relative to Suzie) when the rock hits it. Also find the height of the rock when it hits the van.

Truck:
Xf = Xi + Vo*t + .5 a*t^2
Xf = 5 + 3.2 t + 0

Rock:
Vxf = Vxi = 7.19 m/s after breaking 9.0 m/s at 37 degrees down into x and y components

Xf = Xi + Vxo * t
Xf = 7.19*t

Vyf = Vyo - gt
Vyf = 5.42 - 9.8 t

Yf = Yo + Vyo * t - 4.9 t^2
Yf = 1.6 + 5.42 (1.25) - 4.9 (1.25)^2

The answers I got:

time = 1.25 seconds
Xf relative to Suzie = 9.01 meters
Vf = .7 m above the ground

Is there a mistake?
 
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I haven't checked the numbers but the method looks ok.

-Dan
 
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