Projections of Moments on a new Axis

Click For Summary
SUMMARY

The discussion focuses on calculating moments about a new axis AA, which is parallel to the y-axis and defined by the vector (150j, -100k). The formula for the moment is given as M = u (r x f), where r represents the position vector from any point on the AA axis to the line of force, F. A key clarification is that the moment about the axis is a scalar value derived from the dot product of the unit vector u and the cross product of r and f, expressed as u.(r x f).

PREREQUISITES
  • Understanding of vector mathematics, specifically cross products and dot products.
  • Familiarity with the concept of moments in physics.
  • Knowledge of unit vectors and their application in vector calculations.
  • Basic principles of mechanics related to forces and their effects on objects.
NEXT STEPS
  • Study the application of the cross product in physics problems involving moments.
  • Learn about unit vectors and their significance in vector analysis.
  • Explore scalar and vector quantities in the context of mechanics.
  • Investigate the implications of projecting vectors onto different axes in physics.
USEFUL FOR

Students and educators in physics, particularly those studying mechanics and vector analysis, as well as professionals involved in engineering and applied physics who require a solid understanding of moments and their calculations.

tave
Messages
1
Reaction score
0
Hi all, this is my first post, so forgive me if this is in the wrong forum. (I believe it does belong here)

We are currently doing moments in physics and I have seen this in a few homework problems but can't seem to grasp it.

For example, in one question, we are given a new axis AA that is parallel to the y-axis but is 150j and -100k (150, y, 100) (infinitely long in the y axis?) and the question wants the moment about that new axis AA.

My thinking is that I can take the projection about the y-axis or something along those line (I believe my thinking is completely off here)

M = u (r x f)
where r would be the position vector from the origin to anywhere on the AA axis.
F is the components of the force
u being the unit vector, and where I'm completely clueless.

Again, sorry for the lack of diagram or question, because this is more of a general question that applies to moments in general and axis's that are not touching the origin
 
Physics news on Phys.org
welcome to pf!

hi tave! welcome to pf! :smile:
tave said:
M = u (r x f)
where r would be the position vector from the origin to anywhere on the AA axis.
F is the components of the force
u being the unit vector

no, r is the position vector from anywhere on the AA axis to anywhere on the line of the force

also, it should be u.(r x f), with a dot, so that it's a scalar

the moment (about one particular point on the AA axis) is actually the whole vector r x f,

what we call "the moment about the axis along AA" is really a scalar, the u-component of the whole moment: u.(r x f) …

(when r x f happens be along u, it makes no difference, of course, whether we regard u.(r x f) as a scalar or a vector: when it isn't along u, it's highly unnatural to call u.(r x f) a separate vector)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
7
Views
2K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 9 ·
Replies
9
Views
6K
Replies
7
Views
6K
Replies
2
Views
4K