Proof Linear Span Subsets: Proving L(S) is Smallest Subspace of V

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SUMMARY

The discussion centers on proving that the linear span L(S) of a subset S in a linear space V is the smallest subspace of V containing S, particularly when S is a subset of T, and T is a subspace of V. The proof presented confirms that L(S) is indeed a subset of T, leveraging the definition of span. However, it is noted that the proof lacks the necessary consideration of T being a subspace, which is crucial for a complete argument. The discussion emphasizes the importance of incorporating the properties of subspaces in such proofs.

PREREQUISITES
  • Understanding of linear spans and subspaces in linear algebra.
  • Familiarity with the definitions and properties of vector spaces.
  • Knowledge of set theory, particularly subsets and their relationships.
  • Ability to construct mathematical proofs in the context of linear algebra.
NEXT STEPS
  • Study the properties of linear spans and their relationship to subspaces in linear algebra.
  • Learn about the concept of minimal subspaces and how they relate to spans.
  • Explore examples of vector spaces and their subspaces to solidify understanding.
  • Investigate the implications of subspace properties on proofs involving linear combinations.
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Students of linear algebra, mathematicians focusing on vector spaces, and educators seeking to enhance their understanding of linear spans and subspace properties.

Caroline Fields
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This question asks me to prove a statement regarding linear spans. I have devised a proof but I am not sure if it is substantial enough to prove the statement.

1. Homework Statement

Let L(S) be the subspace spanned by a subset S of a linear space V. Prove that if S is a subset of T and T is a subset of V and if T is a subspace of V, then L(S) is a subspace of T. (This property is described by saying that L(S) is the smallest subspace of V which contains S).

Homework Equations


In part (a) of the question I proved that for S={u1, ..., un}, S is always a subset of L(S).

The Attempt at a Solution


From the definition of the span of S, we know that L(S) is the smallest subspace of V that contains S. Therefore, for any T that is a subset of V such that S is a subset of T, it is clear from the definition of span that L(S) is a subset of T.
Is this proof substantial enough?
 
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Caroline Fields said:
This question asks me to prove a statement regarding linear spans. I have devised a proof but I am not sure if it is substantial enough to prove the statement.

1. Homework Statement

Let L(S) be the subspace spanned by a subset S of a linear space V. Prove that if S is a subset of T and T is a subset of V and if T is a subspace of V, then L(S) is a subspace of T. (This property is described by saying that L(S) is the smallest subspace of V which contains S).

Homework Equations


In part (a) of the question I proved that for S={u1, ..., un}, S is always a subset of L(S).

The Attempt at a Solution


From the definition of the span of S, we know that L(S) is the smallest subspace of V that contains S. Therefore, for any T that is a subset of V such that S is a subset of T, it is clear from the definition of span that L(S) is a subset of T.
Is this proof substantial enough?
No. Because you don't use the fact that T is a subspace.
You can use the fact that L(S) is the smallest subspace containing S or consider L(T).
 

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