Proof of Determinant: Need Help?

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    Determinant Proof
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I need help with proof. Can anyone lead me in the right direction?
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The determinant is a multilinear function of the columns. That means every term in the polynomial expansion of the determinant contains exactly one entry from the first column. How's that for a direction? Think about expanding by minors.
 
Im still lost. I am not understanding.
 
A related problem (actually a special case)... concerning cross-products involving vectors A, B, and M.(A x M) + (B x M) = (A+B) x M

Can you do the 2x2 version of your question? The 1x1 is easy.
 
Dick said:
The determinant is a multilinear function of the columns. That means every term in the polynomial expansion of the determinant contains exactly one entry from the first column. How's that for a direction? Think about expanding by minors.

eyehategod said:
Im still lost. I am not understanding.
Do you know how to "expand by minors"? If so find the determinant on the right by expanding along the first column.
 
Look up 'expansion by minors'. You can turn the first 3x3 determinant into a sum of three 2x2 determinants a_11*A_11-a_21*A_21+a_31*A_31, where A_ij is a 2x2 determinant that doesn't include any elements of the first column. The second one is b_11*A_11-b_21*A_21+b_31*A_31. The important thing is that the A determinants are the same.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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