Proof of Homomorphism: f(eG) = eH

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SUMMARY

The discussion centers on the proof of the homomorphism property f(eG) = eH, where f:G→H is a homomorphism. The proof utilizes the identity element eG in group G and shows that f(eG) behaves as the identity element eH in group H. The key steps involve applying the homomorphism property and the definition of identity elements in groups. The confusion arises from the transition between the first and second lines of the proof, which some participants found unclear.

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Homework Statement


If f:G[tex]\rightarrow[/tex]H is a homomorphism, then f(eG) = eH.


Homework Equations


The proof from my professor's notes:
f(eG) = f(eG*GeG) = f(eG)*f(eG)
f(eG) = f(eG)*eH
f(eG)*f(eG) = f(eG)*eH
f(eG) = eH

The Attempt at a Solution

My question is, how do you get from the first line to the second. Because it looks like she's using the proposition to prove itself.
 
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The second line doesn't follow from the first. It simply says that if you multiply any element of H by the identity element of H, you get ... (fill in the rest).

Petek
 
Petek said:
The second line doesn't follow from the first. It simply says that if you multiply any element of H by the identity element of H, you get ... (fill in the rest).

Petek
:blushing: I feel like an idiot. Thank you!
 

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