Proof of power rule of limit laws

burkley
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Homework Statement


Power Rule: If r and s are integers with no common factor and s=/=0, then
lim(f(x))r/s = Lr/s
x\rightarrowc
provided that Lr/s is a real number. (If s is even, we assume that L>0)
How can I prove it?

Homework Equations





The Attempt at a Solution


I heard that the proof is related to The Sandwich Theorem
 
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From \lim_{x\rightarrow c} f(x)g(x)= \left(\lim_{x \rightarrow c}f(x)\right)\left(\lim_{x \rightarrow c}g(x) you should be able to prove that \lim_{x\rightarrow c}f^2(x)= \left(\lim_{x\rightarrow c} f(x)\right)^2. Then use induction to prove that \lim_{x\rightarrow c}f^n(x)= \lim_{x\rightarrow c}\left(f(x)\right)^n. That's the easy part.

For \lim_{x\rightarrow c} f^{1/m}(x), assuming that limit exists, define g(x)= f^{1/n}(x) and look at lim_{x\rightarrow c}g^n(x).
 
Thank you for answering me. But how can we assume that lim f^1/m(x) exists?
x->c
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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