Proof of Unit Circle: AE = Tan(\theta)

AI Thread Summary
The discussion focuses on proving that AE equals Tan(θ) using a triangle from a diagram. The user initially struggles with the relationship between the sides of triangle OAE and seeks clarification on using similar triangles. A participant clarifies that in triangle OAE, AE is the opposite side to angle θ, while OA is the adjacent side, leading to the conclusion that Tan(θ) equals AE. The conversation confirms that using similar triangles simplifies the proof process, and the user expresses progress in understanding the concept. Overall, the proof of AE = Tan(θ) is established through the relationship of triangle sides and the properties of tangent.
Einstein2nd
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Homework Statement


The problem comes with a diagram but I'll use the wikipedia diagram because it's nice and pretty and I'll just rearrange the letters to suit it.

http://upload.wikimedia.org/wikipedia/commons/9/9d/Circle-trig6.svg

Just in case the image doesn't load in the page: http://upload.wikimedia.org/wikipedia/commons/9/9d/Circle-trig6.svg

Prove that AE = Tan(\theta)

Similar triangles may help.

Homework Equations


Basic similar triangles equations of:

\frac{OF}{AC} = \frac{OE}{AC} = \frac{OA}{FE}

The Attempt at a Solution



After working out the above relationship, I've tried to look specifically at the ACE triangle. I already have AC = sin(\theta) and EC = OE - cos(\theta)

AE = \sqrt{(AC)^{2} + (EC)^{2}}
I need to rearrange it somehow so I get: AE = \sqrt{\frac{sin^{2}(\theta)}{cos^{2}(\theta)}} but I'm not sure how to go about this. I'm getting a bit lost/sidetracked so hopefully you can give me some help. There a part (b) in this question but I won't ask about that until after this and hopefully once I can solve this (b) will be easy.

Thanks in advance for your help.
 
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Hmm. I got an email saying that Integral had replied but nothing is showing here.
 
Welcome to PF!

Hi Einstein2nd! Welcome to PF! :smile:

One definition of tan is: "opposite/adjacent".

In this case, in the triangle OAE, the side opposite theta is AE, and the side adjacent to theta is OA.

So tantheta = AE/OA = AE/1 = AE. :smile:

This is actually the reason why it's called the tangent … it's the length of the tangent!
(… the clue's in the name … :wink:)


Alternatively, using similar triangles as suggested:

Hint: OAE is similar to OCA. :smile:
 
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I may be on the wrong track here but you are saying OE = tan(theta) when I was trying to prove AE = tan(theta). Has there been a mixup with the letters on the wikipedia diagram I gave or is there somethign more to it than that?

Thank you for your help so far!
 
oops!

Hi Einstein2nd! :smile:

Yes, you're right … I got the letters wrong.

I should have written:

In this case, in the triangle OAE, the side opposite theta is AE, and the side adjacent to theta is OA.

So tantheta = AE/OA = AE/1 = AE. :smile:

Sorry! :redface:

"opposite/adjacent" for tan is right! :smile:

(I've edited my previous post to correct this.)

How are you doing with the similar triangles?
 
All done and proven! I then went on to prove Sec, Cosec and Cot! I'll post answer later as I don't have them on me. Proving Tan wasn't that hard in the end. Similar triangles made it very easy.
 
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