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jesuslovesu
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Homework Statement
Prove B^T ~ A^T (tranpose)
Given: B ~ A
Can anyone check if my proof is correct? Towards the end I'm not quite sure if I can do it like that. Do I have to say what P is exactly? The only matrix I can think that would satisfy that is the identity matrix.
Homework Equations
The Attempt at a Solution
B ~ A
B = P^-1 * A * P
B^T = P^T * A^T * (P^-1)^T
so P is a matrix that where P^T = P^-1 therefore (P^T)^-1 = P
B^T = P^-1 * A^T * P
B^T ~ A^T
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