Proof that norm of submatrix must be less than norm of matrix it's embedded in

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SUMMARY

The discussion centers on proving that the norm of a submatrix B must be less than or equal to the norm of the matrix A from which it is derived. The key equation established is ||B|| = ||M_1 * A * M_2||, leading to the conclusion ||B|| <= ||M_1|| * ||A|| * ||M_2||. It is determined that if A is a 4x3 matrix, M_1 must be a 1x4 matrix and M_2 a 3x1 matrix, with the combined product of M_1 and M_2 constrained to be less than or equal to 1. The discussion emphasizes the importance of identifying M_1 and M_2 explicitly to complete the proof.

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Homework Statement



http://dl.dropbox.com/u/4027565/2010-10-10_194728.png

Homework Equations





The Attempt at a Solution




||B|| = ||M_1 * A * M_2 ||

So from an equality following from the norm, we can get...

||B|| <= ||M_1||*||A||*||M_2||.

Now, we know that B is a submatrix of A. So if A is 4x3, then M_1 must be 1x4 and M_2 must be 3X1 (I know that block matrices are more complicated than that, but this might work). What this also means is that the combined product of M_1 and M_2 must be <= 1. But beyond that, I'm stuck. Is there another step I should take?

Thanks!
 
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Okay so if B is ultimately 1x1, then M_1 and M_2 must both be matrices with 0s everywhere except for one row (or column). So the maximum norm (under any situation) would be 1.
 
You cane always embed B in 4x4 block matrices by adding 0 and I as appropriate blocks. Block matrices M_1 and M_2 will probably be orthogonal projections of norm ||M||=1. In any case the key is to find explicitly M_1 and M_2 and their norms. Then use [tex]||ABC||\leq ||A||\,||B||\,||C||.[/tex]
 
Last edited:

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