jeff1evesque
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1. Statement:
The Real Part of a "Complex Number is expressed as the following:
Real(A) = \frac{1}{2}(A + A*) = \frac{1}{2}(|A|e^{j\alpha} + |A|e^{-j\alpha}) = \frac{1}{2}|A|(2cos(\alpha)) = |A|cos(\alpha). (#1)
The Imaginary Part of a "Complex Number" is expressed as the following:
Imag(A) = \frac{1}{2}(A - A*) = \frac{1}{2}(|A|e^{j\alpha} - |A|e^{-j\alpha}) = \frac{1}{2}|A|(2jsin(\alpha)) = j|A|sin(\alpha). (#2)
2. Questions:
I was just curious how \frac{1}{2}|A|(2cos(\alpha)) was derived in equation (#1), and how \frac{1}{2}|A|(2jsin(\alpha)) was derived in equation (#2)?
thanks,
Jeff
The Real Part of a "Complex Number is expressed as the following:
Real(A) = \frac{1}{2}(A + A*) = \frac{1}{2}(|A|e^{j\alpha} + |A|e^{-j\alpha}) = \frac{1}{2}|A|(2cos(\alpha)) = |A|cos(\alpha). (#1)
The Imaginary Part of a "Complex Number" is expressed as the following:
Imag(A) = \frac{1}{2}(A - A*) = \frac{1}{2}(|A|e^{j\alpha} - |A|e^{-j\alpha}) = \frac{1}{2}|A|(2jsin(\alpha)) = j|A|sin(\alpha). (#2)
2. Questions:
I was just curious how \frac{1}{2}|A|(2cos(\alpha)) was derived in equation (#1), and how \frac{1}{2}|A|(2jsin(\alpha)) was derived in equation (#2)?
thanks,
Jeff