Properties of Hermitian Operators: Show Real Expectation Value & Commutativity

AI Thread Summary
The discussion focuses on the properties of Hermitian operators, specifically regarding their expectation values and commutativity. It is established that the expectation value of a Hermitian operator is real, as demonstrated through the integral of the wave function and its conjugate. The condition for the product of two Hermitian operators to also be Hermitian is clarified; they commute (i.e., their commutator is zero) for the product to retain Hermitian properties. Additionally, the discussion touches on the implications of the Hermitian conjugate in determining the nature of the product of two Hermitian operators. Overall, the properties of Hermitian operators are crucial for understanding quantum mechanics.
yakattack
Messages
3
Reaction score
0
I have some questions about the properties of a Hermitian Operators.
1) Show that the expectaion value of a Hermitian Operator is real.
2) Show that even though \hat{}Q and \hat{}R are Hermitian, \hat{}Q\hat{}R is only hermitian if [\hat{}Q,\hat{}R]=0


Homework Equations





The Attempt at a Solution



1) Expectation Value <\hat{}Q>= \int\Psi*\hat{}Q\Psi and for a Hermitian Operator \hat{}Q*=\hat{}Q
Therefore does
1) Expectation Value <\hat{}Q>= \int\Psi*\hat{}Q\Psi=(\int\Psi*\hat{}Q*\Psi )* prove that the expectaion value is real as the complex conjugate = the normal value?

attempt at 2)
AB*=(AB)transpose=BtransposeAtranspose=BA
now if A, B are hermitian this is only true if AB is also hermitian?
 
Physics news on Phys.org
1. Use this TEX parse \hat{Q}.
2. For a vector \psi [/tex], the expectation value of the linear operator A is \langle \psi, A\psi. If A is hermitean, can you show that the exp. value is real ?<br /> <br /> The 3-rd point is a little bit involved.
 
Another question about Hermitians..

If A and B are Hermitian, then is AB also hermitian?

b
 
beerchop said:
If A and B are Hermitian, then is AB also hermitian?

b

think of what the hermitian conjugate is for AB...
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top