Properties of Limits:Lim 2^(1/n) = 2^0 = 1

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Homework Statement



What property of limits says that lim 2^(1/n) = 2^lim (1/n) = 2^0 = 1? Thanks.

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The Attempt at a Solution

 
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It's not a property of limits. It's a property of the function f(x)=2^x. f(x) is continuous at x=0.
 
I don't follow that. Because 2^x is continuous at x = 0, this means that lim 2^x = 2 ^ lim x?
 
f(x) is continuous at x=a means lim x->a f(x)=f(a). That's the definition of continuity. Apply it to f(x)=2^x and a=0.
 
Oh, duh... Thank you so much.
 
But there is a "law of limits" involved:

If \lim_{x\to a} f(x)= L and \lim_{n\to\infty} x_n= a then \lim_{n\to\infty} f(x_n)= L.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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