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## Homework Statement

A proton is accelerated from rest through a potential difference of 107 V. Calculate the final speed of this proton.

## Homework Equations

I'm not really sure which equations to use, but I figured I give all I tried...

V=-Ed

V=PE/q

PE=-qEd

and I think this applies...v(f)^2= v(i)^2 + 2ad

## The Attempt at a Solution

I really can't figure out what equation i should use. What I did was..

1)used the equation V = Ed

2) becomes V= Kc(q/d^2)d

3) becomes V=Kc(q/d)

4)107= 8.99x10^9 (1.602x10^-19)/d

5)Solved for d and found it was 1.34598 x 10^-11

6) used the equation v(f)^2= v(i)^2 + 2ad

7) became v = sqrt (2a (1.34598x10^-11)

....but I don't know what "a" is so I can't solve. Any help would be greatly appreciated. I gave this a shot and really couldn't figure it out. Thanks, everyone.