A proton is accelerated from rest through a potential difference of 107 V. Calculate the final speed of this proton.
I'm not really sure which equations to use, but I figured I give all I tried...
and I think this applies...v(f)^2= v(i)^2 + 2ad
The Attempt at a Solution
I really can't figure out what equation i should use. What I did was..
1)used the equation V = Ed
2) becomes V= Kc(q/d^2)d
3) becomes V=Kc(q/d)
4)107= 8.99x10^9 (1.602x10^-19)/d
5)Solved for d and found it was 1.34598 x 10^-11
6) used the equation v(f)^2= v(i)^2 + 2ad
7) became v = sqrt (2a (1.34598x10^-11)
....but I don't know what "a" is so I can't solve. Any help would be greatly appreciated. I gave this a shot and really couldn't figure it out. Thanks, everyone.