Proton NMR: why does this appear as a multiplet?

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The discussion centers on understanding why a specific proton signal appears as a multiplet in Proton NMR. The user is confused about the concept of a multiplet and seeks clarification on the signal from protons in the molecule. They mention having two "d" protons and one "b" proton, which should theoretically result in a doublet of triplets or a triplet of doublets. Additionally, there is a question raised about why another signal, referred to as "D," is not classified as a multiplet. The conversation highlights the complexities of interpreting NMR signals in relation to proton environments.
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Homework Statement



It asks you to identify the shift and nature of the protons in the molecule.

Picture:

https://mailhost-6.tamu.edu/service/home/~/?auth=co&id=24393&part=2

multiplet.gif


Homework Equations



none

The Attempt at a Solution



I cannot understand what makes C a multiplet. I suppose I am confused about the concept of a multiplet in general.
 
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Sorry, no picture.
 
sorry. what about now?
 
Mitocarta said:
I cannot understand what makes C a multiplet.

Two d protons and single b proton. Together they should yield doublet of triplets (or triplet of doublets).
 
Borek said:
Two d protons and single b proton. Together they should yield doublet of triplets (or triplet of doublets).

why is D not a multiplet ?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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