Prove an integral representation of the zero-order Bessel function

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SUMMARY

The integral representation of the zero-order Bessel function, as stated in Milonni and Eberly's "Laser Physics" (2010), is given by the equation J_0(αρ) = (1/2π) ∫₀²π e^(i[α(ρ cos(φ) + ρ sin(φ))]) dφ. The discussion highlights the transformation of this equation into J_0(αρ) = (1/2π) ∫₀²π e^(i[αρ]) dφ, which simplifies to J_0(αρ) = e^(i[αρ]) after integration. A correction was noted where the variable φ should be replaced with φ' in the integral, leading to the correct representation of the Bessel function.

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  • Understanding of Bessel functions, specifically the zero-order Bessel function.
  • Familiarity with complex exponentials and integration techniques.
  • Knowledge of mathematical notation and transformations in calculus.
  • Access to "Laser Physics" by Milonni and Eberly (2010) for reference.
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  • Learn about integral transforms and their role in solving differential equations.
  • Examine the derivation of Bessel functions from cylindrical coordinates.
  • Explore the handbook of mathematics by Abramowitz and Stegun for additional integral representations.
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Students and researchers in physics, particularly those focusing on optics and wave phenomena, as well as mathematicians interested in special functions and their applications.

Dale12
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Homework Statement


In section 7.15 of this book: Milonni, P. W. and J. H. Eberly (2010). Laser Physics.
there is an equation (7.15.9) which is an integral representation of the zero-order Bessel function:

J_0(\alpha\rho)=\frac{1}{2\pi}\int^{2\pi}_{0}e^{i[\alpha(xcos{\phi}+ysin{\phi})]}d\phi

This equation could also be found in this paper:
Durnin, J. (1987). "Exact solutions for nondiffracting beams. I. The scalar theory." Journal of the Optical Society of America A 4(4): 651.

Homework Equations


here x=\rho cos{\phi}, y=\rho sin{\phi}.

The Attempt at a Solution


Rerwite it as:
J_0(\alpha\rho)=\frac{1}{2\pi}\int^{2\pi}_{0}e^{i[\alpha(\rho cos^2{\phi}+\rho sin^2{\phi})]}d\phi
this lead to:
J_0(\alpha\rho)=\frac{1}{2\pi}\int^{2\pi}_{0}e^{i[\alpha\rho]}d\phi
and after integral of \phi, this becomes
J_0(\alpha\rho)=e^{i[\alpha\rho]}?

Also I tried to look it up in the handbook of mathematics by Abramowitz, M. but failed to find this equation, except one like this:
J_0(t)=\frac{1}{\pi}\int^{\pi}_0 e^{itcos{\phi}}d\phi
this integral from 0 to \pi could be rewritten to 2\pi

J_0(t)=\frac{1}{2\pi}\int^{2\pi}_0 e^{-itcos{\phi}}d\phi

as http://math.stackexchange.com/quest...ic-integral-int-02-pi-e-2-pi-i-lambda-cost-dt
describes.

yet, this is not what I want.

Still, this equation is not found in some wiki pages:
http://mathworld.wolfram.com/BesselFunctionoftheFirstKind.html
http://en.wikipedia.org/wiki/Bessel_function

Thanks for any reply!
 
Last edited:
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Well, I have found that the error appears in step 2.
It should be phi' instead of phi.
after that, it should be rho*cos(phi'-phi) above exp.
and then the integral would be J0.

Thanks anyway!
 

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