Prove Exterior Angle Bisector Property in Triangle ABC & Point D

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1. Prove the property of exterior angle bisectors discussed in class. Given triangle ABC and point D on line AB such that CD bisects the exterior angle at C, then BD/AD=BC/AC.

The only thing I can compute about this problem is the Property of Exterior Angle, but I don't know how to apply it to the problem.

Exterior Angle is the angle between any side of a shape, and a line extended from the next side. <-- That's is all I understand.

Help on where to start this problem out with.

Thanks.
 
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Chemistry101 said:
1. Prove the property of exterior angle bisectors discussed in class. Given triangle ABC and point D on line AB such that CD bisects the exterior angle at C, then BD/AD=BC/AC.

Hi Chemistry101! :smile:

You need to find (ie make) a similar triangle somewhere.

Hint: draw a line through D parallel to BC :smile:
 
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