Prove Idempotency of A: Homework Statement

  • Thread starter Thread starter jmarzouq
  • Start date Start date
  • Tags Tags
    Proof
jmarzouq
Messages
5
Reaction score
0

Homework Statement


Prove that if (A^τ)A = A, then A is idempotent. [Hint: First show that (A^τ)A = A^τ]

Homework Equations


N/A

The Attempt at a Solution


I've gotten to the hint portion by taking the transpose of both sides, but have been unable to get that far past that. I've tried right side multiplying by A^-1 and have gotten this far:
A^τ = A^τ(A^-1), then, taking the transpose of each side yields
A = [(A^-1)^τ]A

I can't figure out how to get rid of the transpose/inverse from there. Any help would be greatly appreciated. Thanks!
 
Physics news on Phys.org
You can't take the inverse because you don't know that A is invertible. Indeed, if A is invertible and idempotent, then A must be the identity matrix. (Can you prove that?)

You are given that A^T A = A, and you have shown that A^T A = A^T. The left hand sides of these two equations are the same, and therefore the right hand sides must also be the same. What does that imply about A?
 
Ah, I see now. So A is equal to its own transpose so you can just substitute A back into the initial equation for A^T and get A^2 = A proving it's idempotent. I really appreciate the help!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top