Prove: Invariant Subspaces are g(T)-Invariant

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To prove that a T-invariant subspace W of a vector space V is g(T)-invariant for any polynomial g(t), one must show that applying g(T) to any vector x in W results in a vector that remains in W. The discussion highlights the confusion regarding whether g(t) is the characteristic polynomial of T, clarifying that g(t) is arbitrary. The approach involves demonstrating that since W is T-invariant, it will also be invariant under the action of g(T). The proof can be simplified by focusing on how g(T) operates on elements of W. Understanding these concepts is crucial for completing the proof effectively.
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Homework Statement


Let T be a linear operator on a vector space V and let W be a T-Invariant subspace of V. Prove that W is g(T)-invariant for any polynomial g(t).


Homework Equations


Cayley-Hamilton Theorem?


The Attempt at a Solution


Im not sure how to begin. Ok so g(t) is the characteristic polynomial of T. If W is a T-Invariant subspace of V, then \forallv\epsilonW, T(v) \epsilon W

So for any T with a characteristic polynomial g(t), W is still T-Invariant...not sure if I am even leading into the right direction. Any help on getting going with this proof?
 
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Just have g(T) act on an arbitrary x in W, and show that the result is in W. This is much easier than you seem to be expecting.

Why are you saying that g is the characteristic polynomial of T? You said that g was arbitrary in the problem statement.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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