Prove: Invariant Subspaces are g(T)-Invariant

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SUMMARY

The discussion centers on proving that if W is a T-invariant subspace of a vector space V, then W is g(T)-invariant for any polynomial g(t). Participants clarify that g(t) is not limited to the characteristic polynomial of T, but can be any polynomial. The proof approach involves demonstrating that for any vector x in W, g(T)(x) remains in W, leveraging the properties of T-invariance. The Cayley-Hamilton theorem is mentioned as a relevant concept, although its direct application to the proof is not fully explored.

PREREQUISITES
  • Understanding of linear operators and vector spaces
  • Knowledge of T-invariant subspaces
  • Familiarity with polynomial functions and their application to operators
  • Basic grasp of the Cayley-Hamilton theorem
NEXT STEPS
  • Study the properties of T-invariant subspaces in linear algebra
  • Learn about polynomial functions of operators, specifically g(T)
  • Explore the Cayley-Hamilton theorem and its implications for linear operators
  • Practice proving g(T)-invariance with various polynomials
USEFUL FOR

This discussion is beneficial for students studying linear algebra, particularly those focusing on linear operators and invariant subspaces. It is also useful for educators seeking to clarify concepts related to operator theory.

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Homework Statement


Let T be a linear operator on a vector space V and let W be a T-Invariant subspace of V. Prove that W is g(T)-invariant for any polynomial g(t).


Homework Equations


Cayley-Hamilton Theorem?


The Attempt at a Solution


Im not sure how to begin. Ok so g(t) is the characteristic polynomial of T. If W is a T-Invariant subspace of V, then \forallv\epsilonW, T(v) \epsilon W

So for any T with a characteristic polynomial g(t), W is still T-Invariant...not sure if I am even leading into the right direction. Any help on getting going with this proof?
 
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Just have g(T) act on an arbitrary x in W, and show that the result is in W. This is much easier than you seem to be expecting.

Why are you saying that g is the characteristic polynomial of T? You said that g was arbitrary in the problem statement.
 

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