Prove its Gauss curvature K = 1

[Shackleford]

Homework Statement

Assume that the surface has the first fundamental form as

E = G = 4(1+u²+v²)^-2

F = 0[/B]

Homework Equations

K = $\frac{-1}{2\sqrt{EG}}[(\frac{E_v}{\sqrt{EG}})_v + (\frac{G_u}{\sqrt{EG}})_u]$[/B]

The Attempt at a Solution

E<sub>v = -16v*(1+u²+v²)^-3

Gu = -16u*(1+u²+v²)^-3</sub>

When I take the partials and find K, I get something messy that doesn't lead me to the conclusion that K = 1.[/B]

 

[RUber]

Start by substituting E=G and \sqrt(EG) = |E|.
What did you end up with?

 

[Shackleford]

Thanks for the reply. I found my error a little bit ago. For some reason, I kept using the denominator of E and G AS E and G. -_- It was late, so I'll credit it to sleep deprivation. Heh.