Prove Rk(A+B) ≤ Rk(A) + Rk(B) - Tal

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The discussion centers on proving the inequality Rk(A+B) ≤ Rk(A) + Rk(B), where Rk denotes the rank of a matrix and R(A) represents the row space of matrix A. The proof utilizes the dimension of the sum of row spaces, stating that Dim[R(A) + R(B)] = Dim[R(A)] + Dim[R(B)] - Dim[R(A) ∩ R(B)], leading to the conclusion that Rk(A+B) is less than or equal to the sum of the ranks of A and B. Additionally, the conversation touches on the relationship between matrices and linear transformations, asserting that properties of matrices apply to linear transformations as well.

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Hey Guys, Another matrice question

Homework Statement


Prove: Rk(A+B)[tex]\leq[/tex] Rk(A) +Rk(B)



The Attempt at a Solution



Rk(A+B) = Dim[R(A) + R(B)]
Where R(A) is the row space of A
we know that Dim[R(A)+R(B)] = Dim[R(A)] + Dim[R(B)] - Dim[R(A)[tex]\cap[/tex]R(B)]
Which means that Dim[R(A)+R(B)] [tex]\leq[/tex] Dim[R(A)] + Dim[R(B)] iff Rk(A+B)[tex]\leq[/tex] Rk(A) +Rk(B)

I heard a rumor that this can also be done with linear transformations, can anyone elighten me on that path?

Is this correct?
Thanks
Tal
 
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talolard said:
Hey Guys, Another matrice question

Homework Statement


Prove: Rk(A+B)[tex]\leq[/tex] Rk(A) +Rk(B)



The Attempt at a Solution



Rk(A+B) = Dim[R(A) + R(B)]
Where R(A) is the row space of A
we know that Dim[R(A)+R(B)] = Dim[R(A)] + Dim[R(B)] - Dim[R(A)[tex]\cap[/tex]R(B)]
Which means that Dim[R(A)+R(B)] [tex]\leq[/tex] Dim[R(A)] + Dim[R(B)] iff Rk(A+B)[tex]\leq[/tex] Rk(A) +Rk(B)

I heard a rumor that this can also be done with linear transformations, can anyone elighten me on that path?
If F is a linear transformation from U to V, then, given specific bases for U and V, there exist a matrix representing F so essentially we can interpret matrices as being linear transformations and vice versa. Any thing true of matrices is true of linear transformations.

Is this correct?
Thanks
Tal
 

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