Prove subring and field of quotients?

  • Thread starter Thread starter katherine1124
  • Start date Start date
  • Tags Tags
    Field
katherine1124
Messages
1
Reaction score
0
How do I show that the set D= { a/b in Q | such that b is not divisible by 5} is a subring of Q. Find the field of quotients (field of fractions) of D.
( Q is the set of rational numbers.)

Thank you.
 
Physics news on Phys.org
To check that it's a subring, I think you need to check closure under addition and multiplication, and check that it contains 0 and 1.

To find the field of fractions, notice it is a subset of Q, that it contains Z, and recall what the field of fractions for Z is.

Though you might prefer to try a more hands on approach in finding the field of fractions, to exercise your understanding of the concepts.

Also, while I mentioned how you might find the field of fractions, proving what the field of fractions is will require a good argument.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top