Prove that the nth energy level of atom has degeneracy n^2

AI Thread Summary
The discussion revolves around proving that the nth energy level of an atom has a degeneracy of n^2. Participants are considering the relationship between quantum numbers, specifically how the azimuthal quantum number l can range from 0 to n-1, and the magnetic quantum number ml can take values from -l to l. There is some confusion regarding the application of summation formulas and how to manipulate them to demonstrate the n^2 degeneracy. The need for clarity on the rules governing allowed values of l and ml is emphasized, suggesting that these rules can be utilized without derivation. The conversation highlights the importance of understanding quantum mechanics principles to arrive at the correct proof.
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Homework Statement


Prove that the nth energy level of an atom has degeneracy equal to n^2.

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The Attempt at a Solution


I was thinking of using the sum from n=1 to N of n = N(N+1)/2 but my professor said i needed to change that equation up a bit to be able to show this. I was also thinking about how l is less than or equal to n-1 and ml is less than l so both of those are sort of n's and together they are n squared? Overall a bit confused.
 
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tententententen said:
I was thinking of using the sum from n=1 to N of n = N(N+1)/2 but my professor said i needed to change that equation up a bit to be able to show this. I was also thinking about how l is less than or equal to n-1 and ml is less than l so both of those are sort of n's and together they are n squared?
Something along that line I guess.
I guess you can use the rules for allowed l and m and don't have to derive them?
 
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