Prove the assumption of uniqueness is not necessary

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SUMMARY

The discussion centers on a proof by contradiction regarding the uniqueness of the additive identity in real numbers. The proof asserts that if there are two additive identities, 0 and 0', then assuming they are not equal leads to a contradiction. The conclusion drawn is that 0 must equal 0'. The confusion arises around the term x' and its implications in the proof.

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Is my proof correct?

Homework Statement


Show that, if there exists a number 0 for which x+0=x for all x∈R, and a number 0' for which x+0'=x for all x∈R, then 0=0'.

The Attempt at a Solution


Proof by contradiction:

Assume, 0≠0'. Then,

x+0=x and x+0'=x'

Such that:

x=x-0 and x=x'-0'

Such that: x-0=x'-0'

Which is a contradiction.
Thus, 0=0'.
 
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I don't see the contradiction...
And what is x'??
 

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