Prove transitive (Relations and functions)

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The discussion revolves around proving the transitive property of relations, specifically that if (a,b)R(c,d) and (c,d)R(e,f), then (a,b)R(e,f). Participants express frustration over the lack of clarity due to the attachment format, suggesting that the question and solution should be typed out for better understanding. There is a call for clearer communication to facilitate assistance with the homework problem. The overall focus remains on the transitive relation and the need for proper formatting in academic discussions. Clear presentation of mathematical problems is essential for effective collaboration.
Suyash Singh
Member advised that both problem statement and solution should be posted inline, not as images

Homework Statement



Question 5 of attached photo

Homework Equations


(a,b)R(c,d) and (c,d)R (e,f) implies (a,b)R(e,f)

The Attempt at a Solution


Attached photo[/B]
 

Attachments

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Type the question. If you are too lazy to do that, then we are too lazy to break our neck trying to read something rotated over 90 degrees :smile: !
 
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Suyash Singh said:

Homework Statement



Question 5 of attached photo

Homework Equations


(a,b)R(c,d) and (c,d)R (e,f) implies (a,b)R(e,f)

The Attempt at a Solution


Attached photo[/B]

Type the question and (preferably) type the solution as well.
 
Hah, I didn't even get that far :mad: ...
 

Thread 'Family of lines that are at a distance of 5 from the origin'

I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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