Proving 1+x is a Unit in a Ring for x^n=0

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Homework Statement



Let R be a ring and x in R such that x^n=0 for some n show that 1 + x is a unit.

I know then that x is a zero divisor and I need to find y such that y(1+x) = 1.
I can see in examples that this works and I can prove it for Z mod n. I can't figure out how to prove it for any ring. Please help
Thanks
 
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If there exist n such that xn, there exist a smallest such n. Assume, without loss of generality that n is the smallest number such that xn= 0. If n= 1, then x= 0, x+1= 1 which is a unit. If n> 1, then xn-1 is not 0. Let u= xn-1. Then u(1+ x)= xn-1+ xn= xn-1= u. Does that lead anywhere? In particular is u a unit?
 
You probably know that you can write 1/(1+x) formally as a power series, 1-x+x^2-x^3+... If x^n=0, that series terminates. Can you show that it's true that (1+x)*(1-x+x^2-...x^(n-1))=1?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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