Proving a fixed point on a function

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SUMMARY

The discussion centers on proving the existence of a fixed point for a continuous function f defined on the interval [0,1], where the range of f is also contained within [0,1]. The key conclusion is that the Intermediate Value Theorem (IVT) is essential for demonstrating that there exists a value c in [0,1] such that f(c) = c. The function g(x) = x - f(x) is introduced as a method to apply IVT effectively, leading to the resolution of the problem.

PREREQUISITES
  • Understanding of the Intermediate Value Theorem (IVT)
  • Knowledge of continuous functions
  • Familiarity with fixed point theorems
  • Basic calculus concepts related to functions and intervals
NEXT STEPS
  • Study the application of the Intermediate Value Theorem in fixed point proofs
  • Explore the properties of continuous functions on closed intervals
  • Learn about Brouwer's Fixed Point Theorem
  • Investigate examples of functions that satisfy the conditions of the problem
USEFUL FOR

Mathematics students, educators, and researchers interested in fixed point theory, particularly those studying continuous functions and their properties within defined intervals.

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Hello guys, this question is kinda bothering me since I'm having trouble with one of the steps in proving it.

The question reads. Assume funciton f is continuous on an interval [0,1], such that the range of f is contained within or equal to [0,1]. Show that for a value of c contained within [0,1] there exists f(c)=c.

I know that the proof process must involve the use of Intermediate Value Theorem, but I can't seem to find a way to show that
k = c, (k is a arbitrary number contained within [0,1].

Any tips /help would be appreciated:biggrin:
 
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Show that for a value of c contained within [0,1] there exists f(c)=c.
That can't possibly be what your question says. Doesn't it say "show that there exists some c in [0,1] such that f(c)=c"? Consider the function g(x) = x-f(x) and apply IVT.
 
Thank you AKG, problem solved ^^

I had a similar idea but both worked out ok.
 

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