Proving Algebraic Identity: $\frac{k^2}{k^2-m^2}$

[Lapidus]

Any help please why the following algebraic identity is true

\frac{k^2}{k^2-m^2} = 1 + \frac{m^2}{k^2-m^2}

thanks

 

[berkeman]

Any help please why the following algebraic identity is true

\frac{k^2}{k^2-m^2} = 1 + \frac{m^2}{k^2-m^2}

thanks

Try putting the two terms on the RHS over a common denominator...

 

[Lapidus]

Of course! Thanks, Berkeman

 

[arildno]

Alternatively, use polynomial division on LHS.

 

[Ivan92]

Or you can multiply both LHS and RHS by (k²-m²) and cancel out the denominators. Probably the easiest way.

 

[Lapidus]

Cool. Now it is more obvios than obvious. Funny, first when I saw it, the equation looked wrong.

Anyway, does anybody know perhaps a good site where there are examples of rearranging and solving algebraic equations (and all the tricks that come along with it)? I know all the rules, but I always liked to have some more practise.

 

[Theory4G]

Ivans92's solution is probably the easiest one but some like the polynomial division as well and are very quick with thes solution . Just practice and youll realize what you like/can best.

 

[Ivan92]

What kind of math are you in? If you can, try getting a textbook related to the math course you have. Textbooks will always have exercises, ranging from basic to challenging.

 

[physiqueper4]

Shame on you Lapidus ! can 'nt you just do the first simple thing, sum the two and find it!