Proving converse of fundamental theorem of cyclic groups

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curiousmuch
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Homework Statement


If G is a finite abelian group that has one subgroup of order d for every divisor d of the order of G. Prove that G is cyclic.


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The Attempt at a Solution

 
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Can you check the question. C_2 x C_2 has subgroups of orders 1,2 and 4, but is not cyclic.
 
matt grime said:
Can you check the question. C_2 x C_2 has subgroups of orders 1,2 and 4, but is not cyclic.

I think the point is that it is supposed to have ONE subgroup of each order. Your example has several subgroups of order 2.