How Do You Prove De Morgan's Law for Union and Complement?

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To prove De Morgan's Law for union and complement, the discussion emphasizes the need to start from axioms of mathematical logic rather than assuming the law itself. The proof involves showing that if an element x is in the complement of the union of sets A and B, then it must not belong to either A or B, thus belonging to both A' and B', leading to x being in A' n B'. Conversely, if x is in A' n B', it must not be in A or B, confirming that x is not in the union (A U B). Participants highlight the importance of clear logical steps and avoiding circular reasoning in proofs. Understanding these foundational concepts can help clarify the proving process.
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Homework Statement



Prove De Morgan's Laws (only (A U B)' = A' n B' part)

Homework Equations



(A U B)' = A' n B'

The Attempt at a Solution



I used this
x does not belong to (A U B)
x belongs to A' and B'
x belongs to A' n B'

now opposite

x belongs to A' n B'
x belogns to A' and B'
x does not belong to A and B

and that's it.
how can this x does not belong to A and B can be changed into
x does not belong to (A U B)' ?

all these proving things are confusing..they are too obvious and that's why i can not do this properly how silly..
Any tips that can be used when solving this kind of questions?

Thankyou!
 
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(x \in A' \cap B') \Rightarrow \neg(x \in A)\wedge \neg (x \in B) = \neg[ (x \in A) \vee (x \in B) ] \Rightarrow (x \in (A \cup B)')

Does that make sense?
 
@dx - you are using demorgans law to prove demorgans law...

You used that form of the law that applies to mathematical logic, to get the same law in a different form in set theory..

So that proof is void
 
@dx - you are using demorgans law to prove demorgans law...

You used that form of the law that applies to mathematical logic, to get the same law in a different form in set theory..

So that proof is void
 
How can you prove anything if you're not allowed to use logic?
 
you can use logic. What i was talking about was a branch of mathematics - mathematical logic. You have to start from the axioms and prove the law that u have used in your proof. Start from the axioms of 'Mathematical Logic', and use those to prove it. It can be proved, but u must do it. Once that is done, rest follows

What you have done is use DeMorgan's Law in ML to prove the same in set theory. That is where u are wrong.
 
you can use logic. What i was talking about was a branch of mathematics - mathematical logic. You have to start from the axioms and prove the law that u have used in your proof. Start from the axioms of 'Mathematical Logic', and use those to prove it. It can be proved, but u must do it. Once that is done, rest follows

What you have done is use DeMorgan's Law in ML to prove the same in set theory. That is where u are wrong.
 
what is this \neg stand for?
 
385sk117 said:

Homework Statement



Prove De Morgan's Laws (only (A U B)' = A' n B' part)

Homework Equations



(A U B)' = A' n B'

The Attempt at a Solution



I used this
x does not belong to (A U B)
x belongs to A' and B'
x belongs to A' n B'
Very good but more precisely: "Let x belong to (A U B)'. Then x does not belong to A U B and so is not in A and is not in B. Therefore x is in A' and x is in B'. Then x is in A' n B'.

now opposite

x belongs to A' n B'
x belogns to A' and B'
x does not belong to A and B
Let x be in A' n B'. Then x is in A' and in B'. Since x is in A', x is not in A. Since x is in B', x is not in B. If x were in A U B, it would have to be in either A or B. Since it is not, it is not in A U B and so is in A' U B'.

and that's it.
how can this x does not belong to A and B can be changed into
x does not belong to (A U B)' ?

all these proving things are confusing..they are too obvious and that's why i can not do this properly how silly..
Any tips that can be used when solving this kind of questions?

Thankyou!
 
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