Proving Integrals: e^(au)sin(bu), e^(au)cos(bu), sec^3u du

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Homework Help Overview

The discussion revolves around proving integrals involving exponential and trigonometric functions, specifically the integrals of e^(au)sin(bu), e^(au)cos(bu), and sec^3u. Participants are exploring methods of integration, particularly integration by parts.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using integration by parts for the first two integrals, suggesting a repetitive application of the method. There are mentions of specific choices for u and dv in the integration process. The third integral is also noted to potentially involve integration by parts, with suggestions for variable assignments. Some participants question the need for proofs versus simply carrying out the integration.

Discussion Status

The conversation is active, with participants providing insights into integration techniques and questioning the nature of the original request for proofs. There is a mix of suggestions and clarifications regarding the integration by parts method, but no consensus on the exact nature of the proofs being sought.

Contextual Notes

Some participants express confusion about whether the request is for proofs of the integrals themselves or for the method of integration by parts. This ambiguity may affect the direction of the discussion.

nameVoid
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looking for proofs of the following integrals

integral ( e^(au)sin(bu)du ) and integral(e^(au)cos(bu)du) and integral (sec^3u du)
 
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The first two can be done by integrating by parts twice. After the second integration, you end up with the integral you started with, and you can solve algebraically for the integral. In both problems, start with u = e^(au) and dv = sin(bu)du or cos(bu)du. After integrating the first time, do it again, with u = e^(au) again, and dv being whatever is left.

The third one can also be done by integration by parts, I believe. Try u = sec u and dv = sec^2(u) du.
 
also remember your trig derivatives:

d/dx(secx)=tanxsecx and
d/dx(tanx)=sec2x
 
[tex]\int \exp(p x) dx = \frac{1}{p}\exp(px) + c[/tex]

Take p = a + b i and equate the real and imaginary parts of both sides. You should be able do this mentally in your head (multiplying the numerator and denominator by the complex conjugate of p isn't that difficult).
 
im looking for somthing along the lines of integration by parts a link to proofs would be nice
 
nameVoid said:
im looking for somthing along the lines of integration by parts a link to proofs would be nice
Your problem isn't a proof. All you need to do is carry out the integration, and I have given you a start on how to do that.
 
Do you mean that you want a proof of the actual method of integration by parts? If so, then consider the product rule of differentiation:

d/dx(f*g)=f'*g + f*g'

Now integrate both sides of the equation and you get you proof.

Is that what you were looking for?
 

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