Proving Kepler's Law: A Math Challenge

paintednails
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kepler's law!

hi, does anybody know how to prove that the eccentricity multiplied by the directrix is equal to \frac {b^2}{a} [\itex]?<br /> <br /> i found that the eccentricity of an ellipse is equal to c/a. <br /> <br /> i also found that the directrix is equal to a/e. the way i see it, if i multiply e and d, then i get <br /> <br /> ed = a<br /> <br /> but how do i prove that a = b^2 / a ?<br /> <br /> please help, thanks &lt;3
 
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paintednails said:
hi, does anybody know how to prove that the eccentricity multiplied by the directrix is equal to \frac {b^2}{a}?

i found that the eccentricity of an ellipse is equal to c/a.

i also found that the directrix is equal to a/e. the way i see it, if i multiply e and d, then i get

ed = a

but how do i prove that a = b^2 / a ?

please help, thanks <3
?? What do you mean by the directrix of an ellipse? A parabola has a directrix but it is a line, not a number.
 
I suspect we have an ellipse with center at the origin, major axis on the x-axis, minor on the y, foci at +/-c, major axis length a, minor length b, and vertical directrices at x=+/-a/e

Ifa=b2/a, then a2=b2, which means you really have a circle.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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