Proving Limit as x Approaches 0 for f(x)/x is 1?

[chem_vo]

Homework Statement

Prove that the limit is 1 as x approaches 0 for the function f(x) / x.

Homework Equations

The Attempt at a Solution

I put the f out in front so I was left with f•Lim as (x → 0) (x/x) so I was left with f•lim(x→0) 1 so I used the limit property and was left with f•1. That was my attempt at proving however I have no idea how to prove it please help.

 

[LCKurtz]

Homework Statement

Prove that the limit is 1 as x approaches 0 for the function f(x) / x.

Homework Equations

The Attempt at a Solution

I put the f out in front so I was left with f•Lim as (x → 0) (x/x) so I was left with f•lim(x→0) 1 so I used the limit property and was left with f•1. That was my attempt at proving however I have no idea how to prove it please help.

You don't "pull the f out in front". $f(x)$ is the notation for a function of $x$. Without knowing the formula defining $f(x)$ the problem can't be worked.

 

[chem_vo]

You don't "pull the f out in front". $f(x)$ is the notation for a function of $x$. Without knowing the formula defining $f(x)$ the problem can't be worked.

That's the only information we were given.

 

[LCKurtz]

Then you can't work the problem. Are you certain that $f(x)$ wasn't defined earlier?

 

[chem_vo]

Then you can't work the problem. Are you certain that $f(x)$ wasn't defined earlier?

Yes I'm certain f(x) was never given.

 

[LCKurtz]

Have you studied functions? Do you understand the function notation such as $f(x) = x^2$ or some other formula? If so you should see that your problem is incompletely stated without knowing the formula.

 

[chem_vo]

Have you studied functions? Do you understand the function notation such as $f(x) = x^2$ or some other formula? If so you should see that your problem is incompletely stated without knowing the formula.

Yes I have studied functions I'm aware what a function is. That was the question given and I'm just trying to make sense of it.

 

[LCKurtz]

Then don't waste any more time on that problem.