Proving Non-Integrability of f(x,y) on [-1,1]×[-1,1]

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SUMMARY

The integral of the function f(x,y) = xy/(x²+y²)² over the region [-1,1]×[-1,1] is proven to be non-Henstock integrable. The discussion highlights that traditional numerical integration techniques in Maple or Mathematica, such as trapezoidal integration, are ineffective for this problem. Participants emphasize the need to analyze the behavior of the function near the singularity at (0,0) and suggest approaching the proof by contradiction. The Henstock-Kurzweil Integral, a concept from Real Analysis, is central to this discussion.

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Homework Statement


Prove \int\int_{[-1,1]×[-1,1]}f(x,y)dA is not Henstock Integrable.

Homework Equations


f(x,y) = \frac{xy}{(x^{2}+y^{2})^{2}}
f(x,y) = 0 if x^{2}+y^{2}=0 on the region [-1,1]×[-1,1]

The Attempt at a Solution


The only hints given is that we will not be able to solve in Maple or Mathematica by using trapezoidable interagtion techniques.

I'm assuming I would start by trying to prove that it is integrable and use contradiction to solve my answer.
 
Last edited:
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The Captain said:

Homework Statement


Prove \int\int_{[-1,1]×[-1,1]}f(x,y)dA is not Henstock Integrable.

Homework Equations


f(x,y) = \frac{xy}{(x^{2}+y^{2})^{2}}
f(x,y) = 0 if x^{2}+y^{2}=0 on the region [-1,1]×[-1,1]

The Attempt at a Solution


The only hints given is that we will not be able to solve in Maple or Mathematica by using trapezoidable interagtion techniques.

I'm assuming I would start by trying to prove that it is integrable and use contradiction to solve my answer.

What does it mean to be Henstock integrable? That's not a term I've ever heard.

[STRIKE]In any case, your second equation above doesn't apply. x2 + y2 ≠ 0 for any real x and y.[/STRIKE]
Edit: Wrote the above without thinking too clearly.
 
Last edited:
Henstock-Kurzweil Integral is used in Real Analysis. I'm pretty sure my class is being taught material that is generally left for graduate school, however since my professor did his PhD studies on it, thinks we can handle it.

As for the second equation, we are to think of f(x,y) as a piecewise function. That way we can deal with when both x and y are zero at the same time.
 
Sorry about that incorrect comment in my previous post. I was thinking x2 + y2 ≥ 0, and that somehow that meant that x2 + y2 ≠ 0.
 
I think it's clear the problem is in 0. Try to find out what the integral is on ##([-1,1]\times[-1,1])\setminus ([-\varepsilon,\varepsilon]\times [-\varepsilon,\varepsilon])## and let ##\varepsilon\rightarrow 0##.
 

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