Proving or Disproving X+Y as Open in Metric Spaces | Homework Help

Mr_Physics
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Homework Statement



Let X and Y be subsets of R^2, both non-empty. If X is open, the the sum X+Y is open.

This is either supposed to be proved or disproved.


Homework Equations





The Attempt at a Solution



This strikes me as false since we are only given the X is open. However, I'm not sure how to disprove it other than creating a direct counter example. Any thoughts?
 
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What can you say about X + {y} if {y} is a singleton? Can you generalize from this?
 
No...I think I might need a hint.
 
X + {y} is just a translated copy of X. Specifically, if y = (a,b), then X + {y} is just X shifted right by a and up by b.

So if X is open, then X + {y} is open.

Now, think about X + Y, where Y is any nonempty set. Think of Y as a union of singletons {y}. Can you express X + Y in terms of the sets X + {y} where {y} are the singletons contained in Y?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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