Proving Rational Roots and Irrationality of \sqrt{2}

  • Thread starter Thread starter Edelman
  • Start date Start date
  • Tags Tags
    Rational Roots
Edelman
Messages
4
Reaction score
0

Homework Statement



Prove that a rational root of a monic polynomial is an integer. Use this to prove that the \sqrt{2} is irrational.

Homework Equations





The Attempt at a Solution



///

I am really not sure where to begin?
 
Physics news on Phys.org


What about the polynomial x-1/2? It seems like there are some conditions missing from your problem statement. I'm guessing that your polynomial is supposed to have integer coefficients - if you start with the case when the polynomial is a quadratic, once you figure that out it should be clear how to proceed with the general case
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top