Proving [Subsets, interior, open ball]

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Homework Help Overview

The problem involves proving that if A is a subset of B, then the interior of A is a subset of the interior of B. The discussion centers around the definitions of interior points and open balls in the context of set theory and topology.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of the definitions of interior points and open balls. There is an attempt to connect the existence of open balls around points in int(A) to points in int(B). Questions arise regarding the conditions necessary for a point to be in the interior of a set.

Discussion Status

The discussion is ongoing, with participants providing guidance on the importance of the definitions involved. There is recognition that the original poster has made progress in understanding the relationship between the interiors of the sets, but further clarification is needed on how to formally conclude the proof.

Contextual Notes

Participants note the significance of the subset relationship between A and B, as well as the necessity of demonstrating that open balls around points in int(A) also lie within B.

Design
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Homework Statement


Prove that if A is a subset of B then int(A) is a subset of int(B).
int(A) = interior of A
int(B) = interior of B

The Attempt at a Solution


Take some y E int(a) , this implies that B(r,y) is a subset of A.
Given that A is a subset of B, we know that B(r,y) is a subset of B.
Now take some z E int(b), this implies that B(r,z) is a subset of B.

I got this much but I don't understand how even if I show that B(r,y) is in B(r,z), this shows that it is an int(A) is a subset of int(B) or am I totally on the wrong track?


thank you
 
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What does it mean precisely for z to be in int(B)? Is this condition satisfied by y in int(A)?
 
fzero said:
What does it mean precisely for z to be in int(B)? Is this condition satisfied by y in int(A)?

It means that there exist a B(r,z) in B. Don't understand what you mean here
 
Design said:
It means that there exist a B(r,z) in B. Don't understand what you mean here

OK, in your original post you showed that for y in int(A), there is a B(r,y) in B. Is there a y that is not in int(B)?
 
fzero said:
OK, in your original post you showed that for y in int(A), there is a B(r,y) in B. Is there a y that is not in int(B)?

No there is no y that is not that is not in int(B) since A is a subset of B.
 
Design said:
No there is no y that is not that is not in int(B) since A is a subset of B.

Well I'd be a bit more careful here. [tex]A \subset B[/tex] is obviously important, but the crucial condition for an object y to be in int(B) is that there is a B(r,y) in B. You have all of the results that you need to finish the proof, you just need to put them in the right order.
 
fzero said:
Well I'd be a bit more careful here. [tex]A \subset B[/tex] is obviously important, but the crucial condition for an object y to be in int(B) is that there is a B(r,y) in B. You have all of the results that you need to finish the proof, you just need to put them in the right order.

Thanks I think I understand what you mean.

How should I piece together the last part about how int(A) is a subset of int(B).
Should i say since the ball came from int(A) it must follow that int(A) is a subset of int(B)?
 
Design said:
Thanks I think I understand what you mean.

How should I piece together the last part about how int(A) is a subset of int(B).
Should i say since the ball came from int(A) it must follow that int(A) is a subset of int(B)?

You've shown that every element of int(A) is also in int(B). Use the definition of a subset.
 

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