Proving the Limit of a Function Using Epsilon-Delta Definition

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Homework Help Overview

The discussion revolves around proving the limit of the function f(x) = x² as x approaches 2, specifically demonstrating that \(\lim_{x \to 2} f(x) = 4\) using the epsilon-delta definition of limits.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the distinction between the terms "find" and "choose" in the context of selecting δ for the proof. There is a focus on how to manipulate the expression |x² - 4| and the implications of bounding |x - 2|.

Discussion Status

Participants are actively questioning the terminology used in the problem statement and how it relates to the process of proving limits. Some guidance has been offered regarding the relationship between δ and ε, but no consensus has been reached on the interpretation of the terms.

Contextual Notes

There is a noted confusion regarding the interpretation of "find" versus "choose," which may affect participants' understanding of the epsilon-delta definition. The discussion also highlights the need for clarity in mathematical language.

azizlwl
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Homework Statement


If f(x)=x2 prove that [tex]\lim_{x \to 2} f(x)= 4[/tex]
Solution given:
We must show that given any ε >0, find δ >0 such that |x2-4|<ε when 0<|x-2|<δ

Choose δ≤1 so that <|x-2|<1
-----------------------------------------------
Confuse between the word 'find' and 'choose'.
 
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azizlwl said:

Homework Statement


If f(x)=x2 prove that [tex]\lim_{x \to 2} f(x)= 4[/tex]
Solution given:
We must show that given any ε >0, find δ >0 such that |x2-4|<ε when 0<|x-2|<δ

Choose δ≤1 so that <|x-2|<1
-----------------------------------------------
Confuse between the word 'find' and 'choose'.

##|x^2-4|=|(x+2)(x-2)|=|x+2|\cdot |x-2|##. So if ##|x-2|<1## how big can ##|x+2|## be? Then once you figure that out, how much smaller than 1 does ##|x-2|## need to be to make the whole thing less that ##\epsilon##?
 


You can "find" many values of [itex]\delta[/itex] that will work and then "choose" one of those. That is the same as "finding" a value.
 


Thanks. My confusion must be interpreting the word "find" as calculate in usual mathematics or physics problems.
 
Last edited:

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