Proving the Measurability of a Function Composition

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    Measurable Proof
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Homework Statement



If f : Rn -> R is Lebesgue measurable on Rn, prove that the function F : Rn * Rn -> R de fined by F(x, y) = f(x - y) is Lebesgue measurable on Rn * Rn.

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The Attempt at a Solution



I am confused by the expression of F(x,y), it seems x-y is equal to x of f(x), how can I prove this question?
 
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You know that \mathbb{R}^n\times\mathbb{R}^n\rightarrow \mathbb{R}^n:(x,y)\rightarrow x-y is continuous and thus measurable right?

The only thing you need to show then is that the composition of measurable functions is measurable...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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