Proving using calculus without trig identity

Click For Summary

Homework Help Overview

The discussion revolves around proving that the derivative of the function F(x) = A sin²(Bx + C) + A cos²(Bx + C) equals zero without using trigonometric identities. Participants are exploring the implications of this requirement within the context of calculus.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using the chain rule and the derivatives of sine and cosine to compute the derivative directly. Others express concern about the necessity of using trigonometric identities, questioning whether it is possible to avoid them entirely.

Discussion Status

The discussion is ongoing, with participants sharing different perspectives on the use of trigonometric identities. Some assert that it is possible to derive F'(x) = 0 without them, while others remain skeptical and emphasize the challenge of adhering to the homework constraints.

Contextual Notes

Participants note that the homework guidelines explicitly prohibit the use of trigonometric identities, which influences their approaches and reasoning in the discussion.

kebabs
Messages
4
Reaction score
0
Please I really need help with this homework question

Prove without trig identity that f`(x)=0 for

F(x)=Asin^2(Bx+C)+Acos^2(Bx+C)
 
Physics news on Phys.org
kebabs said:
Please I really need help with this homework question

Prove without trig identity that f`(x)=0 for

F(x)=Asin^2(Bx+C)+Acos^2(Bx+C)

You're not supposed to use the obvious identity that simplifies this? I suppose you could just use the derivatives of sin and cos along with the chain rule to directly compute the derivative. But eventually you'll need to simplify using some trig identity.
 
I can't use trig identy to solve it
 
I mean I'm not allowed to
 
kebabs said:
Please I really need help with this homework question

Prove without trig identity that f`(x)=0 for

F(x)=Asin^2(Bx+C)+Acos^2(Bx+C)

What is F'(x) if [itex]F(x)=A\sin^2(Bx+C)+A\cos^2(Bx+C)\,?[/itex]
 
SteveL27 said:
You're not supposed to use the obvious identity that simplifies this? I suppose you could just use the derivatives of sin and cos along with the chain rule to directly compute the derivative. But eventually you'll need to simplify using some trig identity.
Are you sure? I was able to get F'(x) = 0 by using the chain rule, and yet I didn't use any trig identity.
 
could you please send me your working for this question??
 
It's really simple - just use chain rule to take the d/dx of the whole expression. No trig or any other kinds of tricks necessary. Are you familiar with the use of chain rule?
 
kebabs said:
could you please send me your working for this question??
This is not permitted at Physics Forums - don't even ask.
 

Similar threads

Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
12
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
1K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
3
Views
2K