Proving Whether an Alternating Series is Divergent or Convergent

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Homework Statement




Determine an explicit function for this sequence and determine whether it is convergent.

an={1, 0, -1, 0, 1, 0, -1, 0, 1, ...}


The Attempt at a Solution



I came up with this function:

an = cos(nπ/2), and wrote that as sigma notation from n=0 to infinity. Is that good or should I use a quadratic?

I don't think it converges because it just oscillates and never changes, but how do I prove that?
 
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Do you have to prove it using epsilon's and stuff??
If so, what is the definition of convergence? What is the negation?
 
see answer 5
 
Last edited:
I don't have to use epsilons. But I have to provide an equation showing it. And is the function I made satisfactory, or should I express it as a quadratic?
 
This sequence has 3 different limit points -1,0 and 1, therefore it does not have a limit.
 
If you reffer to the corresponding series,then it diverges because the general term does not converge to 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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