Proving (∇ x A) x A = (A.∇)A-1/2∇Modulus(A power2)

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The discussion centers on proving the vector calculus identity (∇ x A) x A = (A.∇)A - 1/2∇Modulus(A²). Participants suggest expanding both sides using the Del operator and the cross product, indicating that the proof involves extensive vector algebra. A participant expresses difficulty in achieving the required factor of 1/2 in the term involving Modulus(A²), questioning the distinction between A² and Modulus(A²). The conversation highlights the complexity of vector calculus proofs and the importance of understanding the underlying operations.

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Homework Statement


can someone help prove this

(∇ x A) x A =(A.∇)A-1/2∇Modulus(A power2)

Homework Equations


The Attempt at a Solution


(∇ x A) x A =(A.∇)A-∇(A power2)
 
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Calcululus - lu = Calculus

Have you tried expanding out both sides according to the definition of the Del operator and the cross product?

It looks like a moderately long slog thru vector algebra after that point.
 
SteamKing said:
Calcululus - lu = Calculus

Have you tried expanding out both sides according to the definition of the Del operator and the cross product?

It looks like a moderately long slog thru vector algebra after that point.

Hi
Yes I did but what I achieve is the last term without factor of (1/2), don't know what to do now, what I got is (vector A power 2) and required is 1/2*(Modulus( A square)), is there any difference (A square) and Modulus(A square)
 

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