Pulley dynamics problem 12-205 Hibbeler

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The discussion revolves around solving a pulley dynamics problem from Hibbeler's textbook. Two equations are established to relate the movements of blocks A, B, and C based on the lengths of the strings. The user successfully determines that block A is moving upwards and calculates its acceleration as positive, leading to confusion about whether this indicates an increase in speed. Clarification is provided that while A's velocity is upwards, its acceleration being positive means that the speed is actually decreasing. The conversation highlights common challenges faced in understanding pulley dynamics problems.
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Homework Statement


I have posted the snapshot.

Homework Equations


I have written the distances from the datum line. Since we have two threads, I got two
equations.
2S_A +S_C=L_1

(S_B -S_C)+(h-S_C)=L_2

where L1 and L2 are the lengths of the strings excluding the
parts which remain constant in time.

The Attempt at a Solution

I can now relate B and A as

\dot{S_A}=-\frac{\dot{S_B}}{4}

\ddot{S_A}=-\frac{\ddot{S_B}}{4}

So I get \dot{S_A} =-1 , which means the block A is going upwards.
Now the problem says that the speed of the cable being pulled at B is decreasing
at the rate of 2 ft/s2. So that means \ddot{S_B}=-2 ft/s^2.
So I get \ddot{S_A}= 0.5. I got the first answer right. I have question about
the interpretation of the second answer. Since \ddot{S_A} is positive, does
it mean the speed of block A is increasing ?. My second numerical answer is correct
though.
 

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hi IssacNewton! :smile:
IssacNewton said:
… So I get \dot{S_A} =-1 , which means the block A is going upwards.

Now the problem says that the speed of the cable being pulled at B is decreasing
at the rate of 2 ft/s2. So that means \ddot{S_B}=-2 ft/s^2.
So I get \ddot{S_A}= 0.5 …

Since \ddot{S_A} is positive, does it mean the speed of block A is increasing ?

A's velocity is -1 downward, ie 1 upward.

A's acceleration is positive downward, ie negative upward, so the speed of 1 upward is decreasing. :wink:
 
tim, makes perfect sense. these pulley problems sometime throw me...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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