Pulling Horizontally: Force Problems - Help Needed

  • Thread starter Thread starter avb203796
  • Start date Start date
AI Thread Summary
To determine the force needed to start moving a 175.0 kg block with a static friction coefficient of 0.12, calculate the limiting force using the formula: static friction * normal force (N = mg). For the second part, when pulling two identical blocks with a force of 250.0 N, the net force can be found by subtracting the kinetic friction (0.10) multiplied by the total weight from the applied force. This results in the equation: 250 - 0.10(m1g + m2g) = (m1 + m2)a, allowing for the calculation of acceleration. Understanding these force concepts is crucial for solving the problem effectively.
avb203796
Messages
63
Reaction score
0
Please Help! (Force Problems)

Pulling horizontally on a rope moves a block with a total mass of 175.0 kg. If the coefficient of static friction between the block and the ground/slope is 0.12, what force must be applied to the rope to start the sled moving? If a second identical block is tied to the first block, and both are pulled with a force of 250.0 N, what acceleration will both experience, if the coefficient of kinetic friction is 0.10? Please help! I do not really understand how to approach this problem because I am having understanding forces.
 
Physics news on Phys.org
Part one: what is the weight of your block?
 
First part
Limiting force will be static friction * N = static friction * mg
that you can easliy calculate
Second part
Net force in the direction of motion will be
250 -kinetic friction* (N1 + N2)
= 250 -0.10(m1g + m2g)
= (m1 + m2) a
if you know m 1 and m2 ...you can easily calculate acceleration.

enjoy
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Friction problem of a block sandwiched between 2 surfaces
Replies
6
Views
1K
Calculating Force and Acceleration in a Two Block System with Varying Friction
Replies
6
Views
1K
Force pulling on a string at an angle with a block at the other end
Replies
2
Views
1K
A rope, a pole, and some tension
Replies
11
Views
2K
Newton's Second Law (Pulley Sustem)
Replies
3
Views
2K
Static Friction Required to Keep the System from Moving (Two Boxes)
Replies
16
Views
3K
Pulling a sled across snow with a rope at an angle
Replies
8
Views
4K
Why is the tension force equal to friction force
Replies
9
Views
7K
Work and Energy on a Slope - How Does a Block Move Up with Zero Net Work?
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top