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suppose we have a sinusoidal AC source connected to only a pure inductor of self inductance L ( no resistance at all ) ..then emf induced in the inductor is L * dI/dt and is equal and opposite to the applied emf. but if the induced emf opposes the applied emf , then how can there be a current at all in the circuit and in the inductor ?

Thanks.

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# Pure inductor (only) in AC circuit

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