Pure State without Superposition possible?

rodsika
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Please give an example of pure state without superposition present, is this possible at all?
 
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(By "pure state" do you mean eigenstate?) Superposition is such a fundamental feature of quantum mechanics, that no, I don't think what you say is possible. A state which is an eigenstate of one observable will inevitably be a superposition of different eigenstates for some other observable that does not commute with it.

Even a pure plane wave - it can be regarded as a superposition of ingoing and outgoing spherical waves about some origin. Or - the ground state of a particle in a one-dimensional potential well. It is nondegenerate, and so is not a superposition of any other energy eigenstates. However it may be considered as a superposition of eigenstates of some operator that does not commute with E, such as for example the position operator.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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