Push a Block against a Wall- Static Friction

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A block weighing 13 N is pushed against a vertical wall with a 9 N horizontal force, where the coefficients of static and kinetic friction are 0.62 and 0.42, respectively. The normal force exerted by the wall is equal to the push force, resulting in zero horizontal acceleration since the forces balance out. The vertical forces include gravity and the frictional force, complicating the calculation of vertical acceleration. The discussion emphasizes the importance of using free body diagrams and Newton's laws to analyze the forces acting on the block. Understanding the direction of acceleration is crucial for solving the problem correctly.
Phoenixtears
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Homework Statement



A 9 N horizontal force F pushes a block weighing 13.0 N against a vertical wall (Fig. 6-21). The coefficient of static friction between the wall and the block is 0.62, and the coefficient of kinetic friction is 0.42. Assume that the block is not moving initially.


(Image attached)

Determine the normal force that the wall exerts against the block
9 N (It is the same amount pushing against the block- they should be equal)

Determine the blocks acceleration
m/s^2


Homework Equations



Fk= (Coefficient of K)*N
F=ma
Max= Push- normal
May= Static- mg

The Attempt at a Solution



Alright, I began drawing a force graph. On this graph weight faces down, normal force is exerted left (see attachement), static force is exerted up, and push force is exerted right. Determining the acceleration means horizontally, because the acceleration vertically is 9.8. Now, looking at my equations, only one contains 'a': F=ma. So, what do I know in this equation? I can get mass from the 13 N weight. 13/9.8= 1.32653 mass. That just leaves me to find the force. Going back, the acceleration I am trying to find is horizontal. So, I need to use the push-normal to get my total force. Here's my big problem, don't the push force and the normal force equal each other? So that would leave me with an Ma= 0. What does this mean? What have I done wrong?

Thank you in advance!

~Phoenix
 

Attachments

  • Block Against Wall.gif
    Block Against Wall.gif
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Last edited:
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Hi Phoenixtears,

At this point I cannot view your attachment, but I can point out a couple of things about what you have written.

In the horizontal direction, if the two horizontal forces are equal and opposite, then they will give zero horizontal acceleration like you have found.

In the vertical direction, you seem to be assuming that the acceleration is 9.8m/s^2, which is not true. If an object is in free fall, its acceleration is 9.8m/s^2 downwards, but being in free fall means that gravity is the only force acting on it. However, here there are two forces in the vertical direction: gravity and the frictional force, so you have to use Newton's law to find out what the acceleration is.
 
Draw a free body diagram, if using the textbook knight. Otherwise draw a simple diagram and just as alphysicist suggested use Newtons Laws. You are asked for an acceleration but what direction is it in. Which way do you think it would go, imagine lightly holding a block up against a wall which way would it likely go?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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